#include "stdafx.h"
/*
Section 与 Percent 对应关系：
利润<=Section[i] 时 ， 提成为Percent[i]
*/
int Section[] = { 100000, 200000, 400000, 600000, 1000000 };
double Percent[] = { (double)10 / 100, 7.5 / 100, (double)5 / 100, (double)3 / 100, 1.5 / 100 };
//超过最大限定值时的提成比
double OtherPercent = (double)1 / 100;
int Len = sizeof(Section) / sizeof(int);
/*
说明：
index 在[0,Len) 范围内时，说明 Profit<= Section[Len-1] 或 Profit<=Section[0]
index = Len 时， 说明 Profit > Section[Len-1]
*/
int Split(const double& profit)
{
int index = -1, i=0;
if (profit <= 0.0)
return index;
for (; i < Len; i++)
{
if ((profit/Section[i]) >1.0)
continue;
index = i;
break;
}
//profit>Section[Len-1]时，index赋值为Len
if (i == Len)
index = i;
return index;
}
int _tmain(int argc, _TCHAR* argv[])
{
double Profit=0.0, GiveOut=0.0;
//输入利润
printf_s("利润：");
scanf_s("%lf", &Profit);
//计算应发放奖金
int index = Split(Profit);
double tempprofit = Profit;
while (index>=0)
{
//超过最大限定值
if (index == Len)
{
GiveOut += (tempprofit - Section[Len-1]) * OtherPercent;
tempprofit = Section[Len-1];
}
else
{
double temp;
//tempprofit 是否在 Section[0] 范围内
temp = (index-1)>=0? tempprofit-Section[index-1] : tempprofit-0;
GiveOut += temp * Percent[index];
tempprofit = (index-1)>=0 ? Section[index-1]:0;
}
index = Split(tempprofit);
}
printf_s("应发放奖金:%g\n", GiveOut);
return 0;
}阿雪 阿雪
wxd***108@126.com
7年前 (2018-05-23)